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test(stackflow): Add id/time Test Code #405

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Aug 7, 2023
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26 changes: 26 additions & 0 deletions core/src/utils/id.spec.ts
Original file line number Diff line number Diff line change
@@ -0,0 +1,26 @@
import { id } from "./id";

beforeAll(() => {
jest.useFakeTimers();
});

const getCalculatedId = (time: number) => (time * 1000).toString(16);

test("id - time() 값을 기반으로 유니크한 아이디 값을 반환한다.", () => {
const expectedTime1 = new Date("2023-08-06").getTime(); // 1691280000000
const expectedTime2 = new Date("2023-08-07").getTime(); // 1691366400000

jest.setSystemTime(expectedTime1);

expect(id()).toBe(getCalculatedId(expectedTime1));
expect(id()).toBe(getCalculatedId((expectedTime1 * 1000 + 1) / 1000));
expect(id()).toBe(getCalculatedId((expectedTime1 * 1000 + 2) / 1000));
expect(id()).toBe(getCalculatedId((expectedTime1 * 1000 + 3) / 1000));

jest.setSystemTime(expectedTime2);

expect(id()).toBe(getCalculatedId(expectedTime2));
expect(id()).toBe(getCalculatedId((expectedTime2 * 1000 + 1) / 1000));
expect(id()).toBe(getCalculatedId((expectedTime2 * 1000 + 2) / 1000));
expect(id()).toBe(getCalculatedId((expectedTime2 * 1000 + 3) / 1000));
});
24 changes: 24 additions & 0 deletions core/src/utils/time.spec.ts
Original file line number Diff line number Diff line change
@@ -0,0 +1,24 @@
import { time } from "./time";

beforeAll(() => {
jest.useFakeTimers();
});

test("time - 기본적으로 getTime() 값을 반환하며, 이전 호출과 현재 호출 사이에 시간이 동일한 경우 중복을 방지한다.", () => {
const expectedTime1 = new Date("2023-08-06").getTime(); // 1691280000000
const expectedTime2 = new Date("2023-08-07").getTime(); // 1691366400000

jest.setSystemTime(expectedTime1);

expect(time()).toBe(expectedTime1);
expect(time()).toBe((expectedTime1 * 1000 + 1) / 1000);
expect(time()).toBe((expectedTime1 * 1000 + 2) / 1000);
expect(time()).toBe((expectedTime1 * 1000 + 3) / 1000);

jest.setSystemTime(expectedTime2);

expect(time()).toBe(expectedTime2);
expect(time()).toBe((expectedTime2 * 1000 + 1) / 1000);
expect(time()).toBe((expectedTime2 * 1000 + 2) / 1000);
expect(time()).toBe((expectedTime2 * 1000 + 3) / 1000);
});
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