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已知三角形△ABC AB=25 AC=18 sin∠BAC=0.2 过AB中点K 作KF⊥AB交AC于F ,连接中点K及三角形顶点C,得三角形KFC,求证KFC=V50
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已知三角形△ABC AB=25 AC=18 sin∠BAC=0.2 过AB中点K 作KF⊥AB交AC于F ,连接中点K及三角形顶点C,得三角形KFC,求证KFC=V50
The text was updated successfully, but these errors were encountered: