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三角形△ABC AB=25 #2

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cgfeel opened this issue Dec 4, 2022 · 0 comments
Open

三角形△ABC AB=25 #2

cgfeel opened this issue Dec 4, 2022 · 0 comments
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slogen add slogen to sources

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@cgfeel
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cgfeel commented Dec 4, 2022

已知三角形△ABC AB=25 AC=18 sin∠BAC=0.2 过AB中点K 作KF⊥AB交AC于F ,连接中点K及三角形顶点C,得三角形KFC,求证KFC=V50

@innocces innocces added the slogen add slogen to sources label Dec 4, 2022
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